Physics, asked by anilprakashvishnoi2, 4 days ago

A crane is equilibrium when it holds a load of 50 kn on its cable 15 meters from the pivot. The crane uses a large block of concrete weighing 90kn to balance the load. How far should the concrete block be placed from the pivot

Answers

Answered by vshedge301
0

The crane uses a large block of concrete weighing 90kn to balance the load. How far should the concrete block be placed from the pivot.

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Answered by jonathajulius2008
0

Answer:

8.5 m

Explanation:

MA (Mechanical Advantage) = W/F = Lf/Lw

                                               = 50/90 = Lf/15

                                               = 50 x 15 = 90 x Lf

                                               = 750 = 90 x Lf

                                               = Lf = 750/90

                                               = 8.5 m

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