Question

. A crane lifts a car of mass 1200 kg to a height of 10 metre. Calculate the gravitational potential energy
of the the car at this height.

Answer 1

$\large \underline \bold{Given}$:-

$\: \: \: \: \: \: \: \: \: \: \: \: \: \:$$\sf{mass \: = \: 1200 \: kg}$

$\: \: \: \: \: \: \: \: \: \: \: \:$$\sf{height \: = \: 10 \: m}$

$\large \underline \bold{To \: Find}$:-

$\sf{Calculate \: the \: gravitational \: potential \: energy \: of \: the \: Car \: ?}$

$\large \underline \bold{Usable \: Formula}$:-

$\: \: \: \: \: \: \: \: \: \: \: \: \: \:$$\large\boxed{\sf\red{Ep = mgh}}$

$\sf{here \: ,}$

$\sf{m \: = \: mass \: (in \: kg)}$

$\sf{Ep = gravitational \: potential \: energy}$

$\sf{h \: \: = \: height \: (in \: metre)}$

$\large \underline \bold{Solution}$:-

$\sf{On \: using \: the \: above \: formula}$-

$\: \: \: \: \: \: \: \: \: \: \: \: \: \:$$\sf{Ep = 1200\times 10\times 10}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \:$$\sf{Ep = 1200\times 100}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \:$$\sf{Ep = 12\times 10^{4} \: J}$

$\: \: \: \: \: \: \: \: \: \: \:$$\large\boxed{\sf\pink{Ep = 120 \: KJ}}$

$\small \bold{The \: gravitational \: potential \: energy \: of \: the \: Car \: is \: 120 \: killo \: Joule.}$

Answer 2

Answer:

\large \underline \bold{Given}

Given

:-

\: \: \: \: \: \: \: \: \: \: \: \: \: \: \sf{mass \: = \: 1200 \: kg}mass=1200kg

\: \: \: \: \: \: \: \: \: \: \: \: \sf{height \: = \: 10 \: m}height=10m

\large \underline \bold{To \: Find}

ToFind

:-

\sf{Calculate \: the \: gravitational \: potential \: energy \: of \: the \: Car \: ?}CalculatethegravitationalpotentialenergyoftheCar?

\large \underline \bold{Usable \: Formula}

UsableFormula

:-

\: \: \: \: \: \: \: \: \: \: \: \: \: \: \large\boxed{\sf\red{Ep = mgh}}

Ep=mgh

\sf{here \: ,}here,

\sf{m \: = \: mass \: (in \: kg)}m=mass(inkg)

\sf{Ep = gravitational \: potential \: energy}Ep=gravitationalpotentialenergy

\sf{h \: \: = \: height \: (in \: metre)}h=height(inmetre)

\large \underline \bold{Solution}

Solution

:-

\sf{On \: using \: the \: above \: formula}Onusingtheaboveformula -

\: \: \: \: \: \: \: \: \: \: \: \: \: \: \sf{Ep = 1200\times 10\times 10}Ep=1200×10×10

\: \: \: \: \: \: \: \: \: \: \: \: \: \: \sf{Ep = 1200\times 100}Ep=1200×100

\: \: \: \: \: \: \: \: \: \: \: \: \: \: \sf{Ep = 12\times 10^{4} \: J}Ep=12×10

4

J

\: \: \: \: \: \: \: \: \: \: \: \large\boxed{\sf\pink{Ep = 120 \: KJ}}

Ep=120KJ

\small \bold{The \: gravitational \: potential \: energy \: of \: the \: Car \: is \: 120 \: killo \: Joule.}ThegravitationalpotentialenergyoftheCaris120killoJoule.