Question

A crane lifts a crate upwards through a height of 20 metre. The lifting force provided by the crane is 5kN (5 kilo Newton) . How much work is done by the force​

Answer 1

Answer:

Explanation:

Given,

               Force (F)= 5000 N

               Displacement(S) = 20 m

We know that,

                     Work(W) = Force(F) * Displacement(S)

By substitutuing values from Given,

                      W = 5000 * 20 = 100000 J

∴ The work done by the crane is 100 kJ

Answer 2

Given:-

• Height ,h = 20 m

• Force ,F = 5kN

To Find:-

• Work Done ,W

Solution:-

As we know that Work Done is defined as the product of force and displacement. Here we have to calculate the work done by crane against gravity .

• W = mgh

Where,

m is the mass

g is the acceleration due to gravity

h is the height attained by object.

Force = mg = 5kN

1 kN = 1000 N

Therefore, 5 kN = 5×1000 = 5000 N

Substitute the value we get

→ W = 5000 × 20

→ W = 100000 J

→ W = 100000/1000 Kj

→ W = 100Kj

Therefore,the work done by the crane to lift crate is 100 KiloJoules .