Question

A crane lifts an object of weight 20N through a height of 5m in 40 sec.what is its power​

Answer 1

Answer:

P=W/t

So given s=5m,F=20N,t=40s

P=W/t

P=FS/t

P=20×5/40

P=100/40

P=2.5

Hope it helps

Explanation:

Answer 2

Answer:

• Power (P) of the crane is 2.5 Watts.

Given:

1. Weight of the object (W) = 20 N.
2. Height to which the object is raised (h) = 5 m.
3. Time period (t) = 40 seconds.

Explanation:

_________________________

By the relation we know,

⇒ W = m g h

Where,

• W Denotes Work Done.
• m Denotes Mass.
• g Denotes Acceleration due to gravity.
• h Denotes height to which the body is raised.

Now,

⇒ W = m g h

Substituting the values,

⇒ W = (mg) × h

⇒ W = w × h     ∵[w = mg]

[w Denotes Weight of the body]

⇒ W = 20 N × 5 m

⇒ W = 20 × 5

⇒ W = 100

⇒ W = 100 J.

_________________________

_________________________

From Relation we Know,

⇒ P = W / t

Where,

• P Denotes Power.
• W Denotes Work done.
• t Denotes time period.

Now,

⇒ P = W / t

substituting the values,

⇒ P = 100 J / 40 sec

⇒ P = 100 / 40

⇒ P = 10 / 4

⇒ P = 2.5

⇒ P = 2.5 W

∴ Power (P) of the crane is 2.5 Watts.