Question

A crane stands on level ground. It is represented by a vertical tower AB of height 18 m and a jib AC of length 36 m. A vertical cable hangs from C and is attached to a load at D. The jib is inclined at an angle of 35° to the horizontal line AH.

Answer 1

Answer:

A circus artist is climbing a 20 m long rope, which is tightly stretched and tied from the top of a vertical

pole to the ground. Find the height of the pole, if

the angle made by the rope with the ground level is 300 (see Fig. 9.11).

Class_10_Applications_Of_Trignometry_CircusArtist

Answer:

It can be observed from the figure that AB is the pole.

In ∆ABC,

AB/AC = sin 300

=> AB/20 = 1/2

=> AB = 20/2

=> AB = 10

Therefore, the height of the pole is 10 m

Step-by-step explanation:

hope it will help you

Answer 2

Given :  

AB = 18m

AC = 36m

The jib is inclined at an angle of 35°.

To Find :

height of the pole.

Solution :

A circle artist is climbing a 20 m long rope, which is stretched and tied from the top of a vertical pole to the ground.

In ΔABC,

$\frac{AB}{AC}$ = sin 300

⇒ $\frac{AB}{20}$ = $\frac{1}{2}$

⇒ AB = $\frac{20}{2}$

⇒ AB = 10

Therefore, the height of the pole is 10 m.