Question

A crane take 100s to lift 500kg to a height of 6m. Calculate the Power of Crane. *

Answer 1

Answer:

$\sf{Power} = \Large \sf \frac{Work}{Time}$

$\sf{Power} = \Large \sf \frac{Force×Displacement}{Time}$

$\sf{Power} = \Large \sf \frac{mg×h}{t}$

For g = 10m/s²

$\sf{Power} = \Large \sf \frac{500×10×6}{100}$

$\sf{Power} = \Large \sf{300W}$

For g = 9.8m/s²

$\sf{Power} = \Large \sf \frac{500×9.8×6}{100}$

$\sf{Power} = \Large \sf{294W}$

Answer 2

Answer:

294 joules.

Explanation:

power= work done/ time taken

so here power is =MgH/t

=500×9.8×6/100 (mass=500 kg,g=9.8 m/s² and heigh= 6m.

=294 joules.