a crate is being loaded onto a truck using a ramp. if it is moved with a 2,470N force and 3,650J work is done, then how far was the crate moved.
Answers
Answered by
0
Answer:
1.48 m
Explanation:
Force =2470 N
Work done =3650 J
Work done = force * displacement
Let displacement be 'd'.
3650 =2470 * d
Therefore, d =3650 /2470 =1.477m =1.48m
I hope the ans is correct as I am not absolutely sure but according to my concept, this could be the solving.
Similar questions