Question

A crate moves 10 m to the right on a horizontal surface as a woman pulls on it with a 10-N force. Rank the situations shown below according to the work done by her force, least to greatest.

please answer with explanation​

Answer 1

Answer:

Formula of work done = FScos(x)

1..In first diagram force is acting with horizontal angle zero so net force will act on create is 10N

so work done will positive and increasing

2.. In second one force is action with some angle so net force will act in component of 10N

so it will slightly lower than 10N

3.. in third diagram force is acting perpendicular to the crate so work done become zero..

Hence correct order is

3<2<1 of work done....

Thank you....

Answer 2

Work done will be in the order 1>2>3

• For the first system, the force is acting horizontally. It is in the same direction of motion. Work done is the product of force and displacement, where force is in the direction of displacement.

• In the Case 1, Work done = Force*displacement

                                          = 10*10N = 100N

• In the second case, force is acting diagonally towards the ground. Out of the total force, we notice that a component acts in the vertical direction and the other acts on the right, pulling the box. As the force in the direction of displacement is lesser as compared to the previous case,

                   Work done < 100N

• For the third case, no work is being done as the force and displacement are perpendicular.