Question

A crate of mass m1 = 12.4 kg is pulled by a massless rope up a 36.9° ramp. The rope passes over an ideal pulley and is attached to a hanging crate of mass m2 = 16.3 kg. The crates move 1.70 m, starting from rest. If the frictional force on the sliding crate has magnitude 19.8 N and the tension in the rope is 121.5 N, find the total work done on the sliding crate.

Answer 1

Total work done =

$T_w + F_w + W_w$

Tw = Tension.

Fw = Friction.

Ww= weight.

Work Done = Force * displacement.

Work Done =

$= 121.5 * 1.7 - 21.7*1.7 - 12.4*9.8*sin36.9*1.7 \\= 206.55 - 36.89 - 124.037$

Total Work Done -

= 45.623 J