A cricket ball dropped from the top of a building takes 3s to reach the ground. Calculate the distance the ball moved in the third second of its motion. Take g=9.8m/s^2
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time=3 sec
g=9.8m/s^2
u=0m/s
according to newton 3rd law of equation,
S = ut + 1/2gt^2
= o×2 + 1/2×9.8×(3)^2
S = 44.1 meter
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Answer: 24.5m
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