Question

A cricket ball hits the ground with kinetic energy k at an angle of 30 with the vertical . What will be its kinetic energy at the highest point?

Answer 1

k=1/2mv^2
v(vertical)=vsin60
v(horizontal)=vcos60
at the topmost point only horizontal velocity remain
k(at top)=1/2mv^2cos^2(60)
=k/4

Answer 2

hello friend...!!!

according to the question , we should find the kinetic energy at the highest point 

we know that , K = 1/ 2 m v²

⇒ K '= 1 /2 m ( v cos 60° )

here i had taken cos 60 because the reference is taken from horizontal ( consideration )

therefore ,

K' = (1/2 m v²) ( 1/2 ) ²  { here cos 60° = 1/2 }

therefore ,

K' = K / 4 


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hope it helps...!!!