a cricket ball is dropped from a 20m
a) calculate the speed of the ball when it limits the ground
b) calculate the time taken to fall through this height
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From the third equation of motion
v2 = u2 + 2gh
u=0
v2 = 2*20*10
v = 20 m/s
now from first equation of motion
v = u + at
20 = 0 + 20*t
time (t) = 1s
v2 = u2 + 2gh
u=0
v2 = 2*20*10
v = 20 m/s
now from first equation of motion
v = u + at
20 = 0 + 20*t
time (t) = 1s
antocs142:
can u pls explain the first step pls
I marked u brainiest
It is rude
tht your not answering
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