Question

A cricket ball is hit at 30 degree with the horizontal with kinetic energy K. the kinetic energy at the highest point is

Answer 1

according to the question , we should find the kinetic energy at the highest point 

we know that , K = 1/ 2 m v²

⇒ K '= 1 /2 m ( v cos 60° )

here i had taken cos 60 because the reference is taken from horizontal ( consideration )

therefore ,

K' = (1/2 m v²) ( 1/2 ) ²  { here cos 60° = 1/2 }

therefore ,

K' = K / 4 

Answer 2

xd

answer is 3k/4

hope it helps