Question

A cricket ball is hit so that it travels straight up in air and it aquires 3 sec to reach the maximum height . what will it's initial velocity by solving method

Answer 1

Answer:

Maximum height reaching time, t= 3 sec

as, t= u sin¤ /g and sin¤ here is 90 degree, sin90 degree=1

so, by solving we get u= 30 m/sec

hope this will help you.

Answer 2

Answer:

given time taken to reach maximum height 3 sec

We know that

s = ut -1/2gt^2

s = 3u - 44.1

t = 2u/g

u = gt/2

u = 9.8.3/2

u = 14.7 m/s