Question

A cricket ball is rolled on ice with a velocity of 5.6 m/s and comes to rest after travelling 8 m. Find the coefficient of friction. [g = 9.8 $m/s^{2$]

Answer 1

Answer:

Coefficient of friction is equal to 0.2.

Explanation:

u = 5.6m/s

s = 8m

v = 0 m/s

Substituting it in

v²-u² = 2as

Find the value of a.

We get a= 1.96m/s²

To find coefficient of friction

a = ú * g

1.96 = û * 9.8

û = 0.2 .

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Answer 2

Answer:

refer the above attachment

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