Question

A cricket ball is thrown at a speed of 28m/s in a direction 30° above the horizontal. Calculate maximum height the time taken by the ball to return to the same level, and the horizontal distance from the thrower to the point where the ball returns to the same level.

Answer 1

Use H = usquare sinsquareQ /2g to get max. Height

Use R = u square sin2Q /g to get max. Range

Here Q=30 degree
U=28ms-1