Question

A cricket ball is thrown at a speed of 28m/s in a direction 30° above the horizontal. Calculate (a) max. Height (b) time taken bt the ball to return to the same level (c) the distance from the thrower to the point where the ball return to the same level

Answer 1

Answer:

A cricket ball is thrown at a speed of 28ms-1 in a direction 30∘ above the horizontal. Calculate the time taken by the ball to return to the same level. T=2usinθg=2×28×sin30∘9.8=289.8=2.9s.

or

Given : u=28 m/s θ=30

o

(a) : Maximum height H=

2g

u

2

sin

2

θ

⟹ H=

2×9.8

28

2

×0.5

2

=10 m

(b) : Time of flight T=

g

2usinθ

⟹ T=

9.8

2×28×sin30

=2.86 s

(c) : Range R=ucosθ×T

⟹ R=28×cos30

o

×2.86=69.27 m

Answer 2

Answer:

I gave the ans in form of pic .

I think it is ok