Question

A cricket ball is thrown at a speed of 30 m/s in a direction 600 above the horizontal.
Calculate i) the maximum height ii)the horizontal distance from the thrower to the point
where the ball returns to the same level.

Answer 1

Answer:

Given : u=28 m/s θ=30

o

(a) : Maximum height H=

2g

u

2

sin

2

θ

⟹ H=

2×9.8

28

2

×0.5

2

=10 m

(b) : Time of flight T=

g

2usinθ

⟹ T=

9.8

2×28×sin30

=2.86 s

(c) : Range R=ucosθ×T

⟹ R=28×cos30

o

×2.86=69.27 m