Question

A cricket ball is thrown at a speed of 56 m/ sec in a direction making an angle 30 degree with the horizontal calculate a) Maximum height​

Answer 1

Answer:

it is the case of projectile hence,

For maximum heigt : H=

2g

u

2

sinθ

=56

2

×0.5/20=78.4m

Time of flight, T=

g

2usinθ

=

10

2×56×0.5

=5.6s

Range, R=

g

u

2

sin2θ

=

10

56

2

×

3

/2

=271.5m