Question

A cricket ball is thrown at a speed of 56m/s in a direction 30° above the horizontal. Find the range

Answer 1

If you take g=9.8ms^2 then we get the answer shown below, maximum height, H=u^2×sin^2X /2×g=56^2×sin30/9.8=40meter. Time taken,T= 2×u×sinx/g=2×56×sin30/9.8=5.71 second. Distance traveled, R=u^2×sin2x/g= 56^2×2sin30×cos30/9.8=277.1 meter

Answer 2

Given,

U= 56

Angle=30°

Now,range=u^2 sin2*30/g

={56}^2*sin120°/10. I am using g=10

=217.58 ,. After calculation