Question

A cricket ball is thrown into air at a speed of 16 m/s in the direction 30° above the horizontal. What is horizontal distance from the thrower to the point where it returns to same level? (take g = 10 m/s2)​

Answer 1

Explanation:

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Answer 2

HELLO DEAR,

GIVEN:- A cricket ball is thrown into air at a speed of 16 m/s

in the direction 30° above the horizontal. What is horizontal distance from the thrower to the point where it returns to same level? (take g = 10 m/s2).

SOLUTION:-

By using the formula ' Range of Projectile motion '.

R = (u².sin2Ф) / g

where u = 16 m/ s,

Ф = 30°

g = 10 m/s²

So, by putting the value in above equation, we get the

R ={ ( 16 ) ² . sin2×30° } / 10

R = { 256. sin60° } / 10

R = { 256× √3 } / 10

R = 22.17 m

Therefore, the answer is 22.17 meter.

THANKS.