Question

a cricket ball is thrown vertically upwards with an acceleration of 10m/s square
reaches a maximum height of 5m find the initial speed of the ball and the time taken to reach the highest point?

Answer 1

v = 0m/s

s = 5m

a = 10m/s²

Using equation,

v²=u²+2as

0 = u²+2(-10)(5)

0 = u²-100

u² = 100

u = 10m/s

Initial speed of ball = 10m/s

Now,

using equation,

s = ut+½at²

5 = 10t+½×(-10)t²

5 = 10t-5t²

5t²-10t+5 = 0

(5t²-5t)+(-5t+5) = 0

5t(t-1)-5(t-1) = 0

(5t-5)(t-1) = 0

t = 1

Total time taken to reach the highest point = 1second

Cheers!

Answer 2

Explanation:

Above Given Answer Is corrext