Question

A cricket ball is thrown with a velocity of 15 m/s at an angle of
30
∘
30∘
with the horizontal. The time of flight of the ball will be:

(
g
=
10
m
s
−
2
)
(g=10ms−2)

Answer 1

Hope this helps. ...

Answer 2

Given:

Initial velocity (u) = 15 m/s

Angle made with horizontal (α) = 30°

To Find: Time of flight of ball (T)

Calculation:

• Projectile motion is the motion of an object which is thrown at an angle with horizontal axis.
• Time of flight is the time taken by the object to touch the surface after the projectile.

Time of flight:

$\frac{2*u*sin\alpha }{g} = \frac{2*15*sin30}{10} =\frac{2*15*0.5}{10} =1.5$s

Answer:

Time of flight for the cricket ball thrown at 30° is 1.5 seconds.