Question

a cricket ball is thrown with velocity 30 metre per second find the maximum horizontal range on the earth and those two directions along with when the ball is thrown range comes out to be 45 metre in each case.(g=10m/s^2)

Answer 1

Answer:

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Explanation:

Maximum horizontal distance, R=100m

The cricketer will only be able to throw the ball to the maximum horizontal distance when the angle of projection is 45

∘

, i.e., =45

∘

.

The max horizontal range for a projection velocity v is given by the relation:

R

max

=

g

u

2

100=

g

u

2

The ball will achieve the maximum height when it is thrown vertically upward. For such motion, the final velocity v is zero at the maximum height H.

Acceleration, a=g

Using the third equation of motion:

v

2

−u

2

=−2gH

H=u

2

/2g=100/2=50m