Question

a cricket ball is thrown with velocity 30m/s. find the maximum horizontal range on the earth and those two directions along which the ball is range comes out to be 45 degree in each case​

Answer 1

Answer:

Horizontal distance traveled by ball in the air = ut horizontal distance traveled by car in time t = s = ut +(1/2)at² now distance between ball and car = s s = ut +(1/2)at² - ut = (1/2)at² .....eq (1) Now here to calculate the above distance we need to have the value of time t. so, to calculate time we are using v = u + at Ball goes up with the velocity with initial velocity = 9.8 m/s Ball reaches the maximum height

Explanation: