Question

a cricket ball moving horizontally with a velocity 12 m/s is brought to rest by a player in 0.1s if the cricket ball weighs .15kg calculate impulse of a force and avg force applied

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Answer 1

Answer:

time=0.1s

mass m=150

=1.5×10-1 kg

change in velocity=final-intial

velocity=20-(-12)=32 m/s

therefore force = mass*change in velocity/time = 1.5×10-1×32÷0.01

15×32=480N

Answer 2

Answer:

how to find impulse in this question