Question

A cricket ball of mass 0.1 kg moving at a speed of 30 M per second is brought to rest by player in 0.03 seconds. find the average force applied by the player (Ans:720 Newton)

Answer 1

mass = m = 0.1 kg
initial velocity = u = 30m/s
final velocity = v = 0m/s
time interval = t = 0.03s



According to the newtons 2nd law of motion

Force = rate of change in momentum
F = ∆P/∆t
F = mv-mu/∆t
F = m(v-u)/∆t
F = 0.1(0-30)/0.03
F = 0.1(-30)/0.03
F = -100 N

Answer 2

Answer:

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