Question

a cricket ball of mass 0.15 kg is moving with a velocity of 1.2m/s. find the impulse on the ball and average force applied by the player if he stops ball in 0.18s.

Answer 1

impulse=m*v= 0.15*1.2=0.18 is the impulse on the ball
Force= Impulse/time= 0.18/0.18=1 is the avg. force applied by the player

Answer 2

Answer:-0.18 ns, -1n s

Explanation:impulse=m(v-u)=0.15(0-1.2)=-0.18ns

Force=m(v-u)÷t=0.18÷.18=1