Question

a cricket ball of mass 0.15 kg is moving with velocity of 1.2 M per second. find the impulse on the ball and the average force applied by the player if he is able to stop the ball in 0.18 second.

Answer 1

momentum(p) =m×v
p = 0.15×1.2
p=0.18kgm/sec
Force =ma
F= mv/t
F= 0.15×1.2/0.18
F= 0.18/0.18
F=1newton
therefore momentum =0.18kgm/sec
Force= 1newton is answer
Hope it helps u friend

Answer 2

momentum of the ball=mv=.15×1.2=.18kgm/s
impulsive force =change in momentum/time=.18/.18=1 kgm/s²=1N