Question

A cricket ball of mass 0.15kg is moving with a velocity of 2m/s .find the impulse on the ball and force applied by the player if he is also to stop the ball in 0.18s​

Answer 1

Answer:

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Answer 2

Answer:

A cricket ball of mass 0.15kg is moving with a velocity of 2m/s. The impulse on the ball will be $0.3\ kgm/s$  and force applied by the player if he is also to stop the ball in 0.18s​ will be $1.6666\ N$

Step-by-step explanation:

According to Newton's second law of motion,

$F = ma$                ...(1)

where,

F - The force

m - The mass of the object

a - The acceleration due to gravity

We know the impulse (p) is the product of mass (m) and velocity (v).

Or $p = mv$            ...(2)

Then the acceleration can be expressed as,

$a = \frac{v}{t}$                     ...(3)

Substitute equation(3) in (1) and then in (2)

$F = m\times \frac{v}{t} =\frac{p}{t}$     ...(4)

In the question, it is given that,

$m = 0.15 \ kg$

$v = 2\ m/s$

$t = 0.18\ s$

Substitute these values into equation (2)

$p = 0.15\times2= 0.3\ kgm/s$

then, equation(4) becomes,

$F = \frac{0.3}{0.18} = 1.6666\ N$

So,

The impulse =  $0.3\ kgm/s$

The force applied by the player in $0.18\ s$  $=\ 1.6666\ N$