a cricket ball of mass 0.16 kg moving with speed of 20m/s is stopped by a player in 0.1 seconds calculate average force applied by the player
Answers
Answered by
14
hey
here's ur answer
F= m.|a|
where m is mass and a is acceleration.
m = 0.16 kg
u = 20 m/s
v= 0 m/s
t = 0.1 s
so a= (0-20)/0.1 m/s^2
= -200 m/s^2
:. Force = 0.16 kg * 200 m/s^2
= 32 kgm/s^2
= 32 N. (Answer).
HOPE IT HELPS!
here's ur answer
F= m.|a|
where m is mass and a is acceleration.
m = 0.16 kg
u = 20 m/s
v= 0 m/s
t = 0.1 s
so a= (0-20)/0.1 m/s^2
= -200 m/s^2
:. Force = 0.16 kg * 200 m/s^2
= 32 kgm/s^2
= 32 N. (Answer).
HOPE IT HELPS!
Answered by
5
F = m dv/dt
= 0.16 * (20) / 0.1
= 32 N
Average Force applied by player is 32 N
= 0.16 * (20) / 0.1
= 32 N
Average Force applied by player is 32 N
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