Question

A cricket ball of mass 0.16 kg. travelling at 25 m/s is intercepted by a player who fields it cleanly in
0.2 s. The force exerted on his hands is
(1) 20 N
(2) 25 N
(3) 30 N
(4) 40N​

Answer 1

${ \huge \bf { \mid{ \overline{ \underline{Question}}} \mid}}$

A cricket ball of mass 0.16 kg. travelling at 25 m/s is intercepted by a player who fields it cleanly in 0.2 s. The force exerted on his hands is?

$\huge{\bold{\underline{\underline{....Answer....}}}}$

$\huge{\bold{\underline{Given:-}}}$

• Mass of the ball (m) = 0.16 Kg.
• Initial velocity (u) = 25 m/s.
• Final velocity (v) = 0 m/s.
• Time period (t) = 0.2 seconds.

$\huge{\bold{\underline{Explanation:-}}}$

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Applying First kinematics equation,

$\large{\boxed{\tt v = u + at}}$

Substituting the values,

$\large{\tt \leadsto 0 = 25 + a \times 0.2}$

$\large{\tt \leadsto a \times 0.2 = - 25}$

$\large{\tt \leadsto a = \dfrac{- 25}{0.2}}$

$\large{\tt \leadsto a = \dfrac{- 25 \times 10}{2}}$

$\large{\tt \leadsto a = \dfrac{- 25 \times \cancel{10}}{\cancel{2}}}$

$\large{\tt \leadsto a = - 25 \times 5}$

$\large{\leadsto {\underline{\underline{\tt a = - 125 \: m/s^2}}}}$

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Now, Applying Newton's second law of motion,

$\large{\boxed{\tt F = ma}}$

Substituting the values,

$\large{\tt \leadsto F = 0.16 \times - 125}$

$\large{\tt \leadsto F = - 20}$

Taking Magnitude of the Force, will give.

$\huge{\boxed{\boxed{\tt F = 20 \: N}}}$

So, the Force Exerted by the Players hand is 20 Newton's (Option- 1).

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