Question

A cricket ball of mass 0.25kg is moving with a velocity of 1.2m/s find the impulse of the ball and force applied by the player if he is able to stop the ball in 0.18s

Answer 1

Force will be 1.65 N

I will be 0.3 kgm/s

Answer 2

Answer:

A cricket ball of mass 0.25kg is moving with a velocity of 1.2m/s.

The impulse of the ball  will be $0.3\ kgm/s$ and force applied by the player if he is able to stop the ball in 0.18s will be $1.6666\ N$

Explanation:

If F is the force, m is the mass and a is the acceleration due to gravity,

According to Newton's second law of motion,

$F = ma$                ...(1)

We know the impulse (p) is the product of mass (m) and velocity (v).

Or $p = mv$            ...(2)

Then the acceleration can be expressed as,

$a = \frac{v}{t}$                     ...(3)

Substitute equation(3) in (1) and then in (2)

$F = m\times \frac{v}{t} =\frac{p}{t}$     ...(4)

In the question, it is given that,

$m = 0.25 \ kg$

$v = 1.2\ m/s$

$t = 0.18\ s$

Substitute these values into equation (2)

$p = 0.25\times1.2= 0.3\ kgm/s$

then,equation(4) becomes,

$F = \frac{0.3}{0.18} = 1.6666\ N$

So,

The impulse =  $0.3\ kgm/s$

The force applied by the player in $0.18\ s$  $=\ 1.6666\ N$