Question

A cricket ball of mass 0.25kg is moving with a velocity of 1.2m/s find the impulse of the ball and force applied by the player if he is able to stop the ball in 0.18s

Answer 1

Explanation:

ur answer is in the attachment given below

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Answer 2

Answer:

Impulse = 0.3 Newtons

Force = 0.167 Newtons

Explanation:

Given:

• Mass of the cricket ball = 0.25 kg
• initial Velocity of the ball = 1.2 m/s
• Final velocity of the ball = 0 m/s
• Time taken = 0.18 seconds

To find:

• Force applied by the player

Here first we have to find the impulse:

Impulse = m × ΔV

Impulse = 0.25 × 1.2-0

Impulse = 0.3 N

Force = $\dfrac{Impulse}{Time}$

Force = $\frac{0.3}{1.8}$

Force = 0.167 Newtons

The force applied to stop the ball is equal to 0.167 Newtons