Physics, asked by Rahaman1111, 1 year ago

A cricket ball of mass 0.25kg with speed 10m/s collides with a bat and return with same speed within 0.01. The force acted on bat is (a) 25 N (b) 50 N (C) 250N (d) 500 N

Answers

Answered by Anonymous
4
Mass = 0.25 kg, velocity =10m/s
So, change in momentum = 2mv = 2×0.25×10= 5
Force = P/t = 5/0.01 = 500 N....

Hope this helps you....

Chiris: he hasn't mentioned the unit of 0.01..
Anonymous: obviously it would be in sec only...
Chiris: hn
Chiris: i took it the same..
Chiris: and see.
Chiris: our answers match...
Anonymous: the answer should be 250 N only...
Chiris: hn...
Chiris: wrote the same...
Anonymous: I corrected it...
Answered by Chiris
1
hope its helpful. . . . . . .
Attachments:

Rahaman1111: wrong bro
Rahaman1111: The cricket ball mass of 0.25kg moving 10m/s so the change in momentum would be equal to p= 2mv=5kg -m/s and thus the force would be equal to F =p/t= 5/0.01 N= 500M
Rahaman1111: that's mechanism bro
Chiris: oo
Chiris: btw thnx for right ans
Anonymous: sry for wrong answer...
Chiris: apologies
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