A cricket ball of mass 0.2Kg moves with a velocity of 20m/s and is bought to rest by a Player in 0.1 sec . Calculate average force applied by a Player .
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Answered by
10
Force = Mass × Acceleration!
= 0.2 × (20-0)/0.1
= 40 N
= 0.2 × (20-0)/0.1
= 40 N
Answered by
8
a = v - u /t = 0 - 20 / 0.1 = - 200 m/s²
F = ma = 0.2 x -200 = -40 N
Minus sign indicates that force is applied in the opposite direction of motion to that of the ball.
∴ The force applied by player is 40N
F = ma = 0.2 x -200 = -40 N
Minus sign indicates that force is applied in the opposite direction of motion to that of the ball.
∴ The force applied by player is 40N
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