a cricket ball of mass 0.4 kg moving with a velocity of 72 km/h is brought to rest by a player . what is magnitude of the average force exerted by a player?
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The initial velocity of the cricket ball is
=72km/hr = 20m/s
The final velocity of the cricket ball is
=0m/s (as it comes to rest)
Force = mass × acceleration
=mass × (v-u)/t
=0.4×(20)/t
=8/t
Since t is too small F can be 8 or more than height.
HOPE IT HELPS..... :-)
=72km/hr = 20m/s
The final velocity of the cricket ball is
=0m/s (as it comes to rest)
Force = mass × acceleration
=mass × (v-u)/t
=0.4×(20)/t
=8/t
Since t is too small F can be 8 or more than height.
HOPE IT HELPS..... :-)
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