A cricket ball of mass 0.4 kg moving with a velocity of 72km/h is brought to rest by a player. What is the magnitude of the average force exerted by the player?
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M=0.4kg
V=70km/h=20m/s
U=0
Now,impulse =final momentum- initial momentum
=0.4×0-0.4×20
=-8kgm/s
Impulse = F×t
-8N=F×t
Therefore the average force= 8N
V=70km/h=20m/s
U=0
Now,impulse =final momentum- initial momentum
=0.4×0-0.4×20
=-8kgm/s
Impulse = F×t
-8N=F×t
Therefore the average force= 8N
SethRollins1:
Answer given is 40 newton. please try again.
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