Question

A cricket ball of mass 0.5 kg moving at a speed of 30 metre per second is brought to rest by a player in 0.03 seconds find the average force applied by the player(ans:720 Newton)

Answer 1

mass = m = 0.1 kg
initial velocity = u = 30m/s
final velocity = v = 0m/s
time interval = t = 0.03s

According to the newtons 2nd law of motion

Force = rate of change in momentum
F = ∆P/∆t
F = mv-mu/∆t
F = m(v-u)/∆t
F = 0.1(0-30)/0.03
F = 0.1(-30)/0.03
F = -100 N

Answer 2

Answer: 500N

Explanation:30=a×0.03

a= 1000

F=0.5 ×1000

F=500 N