Question

A cricket ball of mass 0.5 kg strikes a cricket bat normally with a velocity of 20 m s-1 and rebounds

with a velocity of 10 m s-1

. The impulse of the force exerted by the ball on the bat is.

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Answer 1

Answer:

Impulse = 15 Ns

Explanation :

Impulse = Fdv

I = ma.dv

I = 0.5 * [20 - ( - 10)]

I = 0.5 * 30

I = 15 Ns

Answer 2

Answer:

15 N sec .

Explanation:

Given :

Mass of cricket ball = 0.5 kg

Initial velocity u = 20 m / sec

Final velocity v = 10 m / sec

We are asked to find Impulse :

We know :

Impulse = Force × Time

OR

Impulse = Change in momentum .

i.e. I = m Δ v

I = 0.5 × ( 10 - ( - 20 ) ) N sec

I = 0.5 × 30 N sec

I = 15 N sec .

Therefore , impulse of the force exerted by the ball on the bat is  15 N sec .