Question

A cricket ball of mass 100 g moving with a speed of 30 m/s is brought to rest by a player in 0.03 s. Find • the change in momentum • the average force applied by the player. plz tell the answer correctly and stepwise​

Answer 1

Answer is in the pic and i hope you got each and every step clearly without any doubts.

Answer 2

Answer:

Change in momentum = - 3kg m/s

Force applied by the player = -100 N

Step by step explanations :

Given that,

A cricket ball of mass 100 g moving with a speed of 30 m/s

here,

mass of ball = 100 g

= 0.1 kg

initial velocity = 30 m/s

it brought to rest by a player in 0.03 s.

so,

final velocity of the ball = 0 m/s

to find,

_____________________

• The change in momentum

~> change in momentum =

final momentum - initial momentum

so,

∆ momentum = m(v - u)

here,

v = 0 m/s

u = 30m/s

m = 0.1 kg

so,

∆ momentum = 0.1(-30)

= -3 kg m/s

___________________

• Average force applied by the player

= mass of the ball × retardation produced

here,

acceleration = (v - u) t

t = 0.03 s

so,

acceleration = -30/0.03

= -1000 m/s²

so,

force applied by the player = 0.1 × 1000

= -100 N

NOTE :

Nagation of force shows motion of ball against force

so,

___________________

Change in momentum = - 3kg m/s

Force applied by the player = -100 N