A cricket ball of mass 100 g moving with a speed of 30 m/s is brought to rest by a player in 0.03 seconds find:1.The change in momentum of ball 2. The average force applied by the player
Answers
Answered by
6
initial momentum =mv=0.1*30=3
final momentum = 0
change in momentum=3
a=v-u/t
=0-30/0.03
-1000m/s^2
f=ma=0.1*-1000
=-100N
final momentum = 0
change in momentum=3
a=v-u/t
=0-30/0.03
-1000m/s^2
f=ma=0.1*-1000
=-100N
Ruchir1234:
Pls make my answer brainliest
Similar questions