A cricket ball of mass 100 g moving with a speed of 40 m/s is brought to rest by a player in 0.04 seconds. Its change in momentum and average force is
Answers
Explanation:
mass of the ball (m) =100g or 0.1kg
initial velocity (u) =25
s
m
time (t) = 0.025sec.
final velocity (v) = 0
Initial momentum = mu
= 0.1×25
= 2.5
s
kgm
Final momentum = mv (which is equal to 0, since v is zero)
Change in momentum = mv-mu
= 0 - 2.5 = -2.5
s
kgm
Average force =
time
Changeinmomentum
= -
0.025
(2.5)
= -100
s
kgm
= -100 N
The negative sign actually shows that the force was applied
opposite to the direction of the motion of the ball.
So, the average force applied by the player will be 100
Hope it helps you
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