a cricket ball of mass 100 g strike the hand of a player with the velocity of 20 metre per second and is brought to rest in 0.01 seconds what is the force applied by the end of this player
it's urgent
Answers
Answered by
1
Answer:
Given mass of the ball as 100 g after converting to mks system it becomes 0.1 kg. As we know that acceleration is nothing but rate of change velocity and in this case we have initial velocity as 20m/s and final velocity as 0.
a=(v−u)/t⇒
a=(0−20)/0.01=−2000m/s
2
F=m×a⇒
F=0.1×2000=200 N.
The hand apply equal and opposite force of 200 N.
Similar questions