a cricket ball of mass 100 gram moving at a speed of 30 metre per second is brought to address by a player in 0.03 seconds find the average force applied by the player
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Answered by
34
10000 Newton's
V=U+AT
30=0+A*0.03
A=100 M/S^2
F=MA
F=100*100
F=10000 Newtons
V=U+AT
30=0+A*0.03
A=100 M/S^2
F=MA
F=100*100
F=10000 Newtons
Answered by
28
m = 100g = 0.1kg
v = 30 m/s
t= 0.03s
f = mv/t = 0.1/0.03 = 3.33333..
or 3.4 N <approx.>
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v = 30 m/s
t= 0.03s
f = mv/t = 0.1/0.03 = 3.33333..
or 3.4 N <approx.>
PLZ MARK MY ANSWER AS BRAINLIEST AS SOON AS POSSIBLE! ! ! ! ! ! ! ! ! !
HOPE IT WILL HELP YOU. . . . . . . . . . . .
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