a cricket ball of mass 100 grams is moving with a velocity of 10 metre per second and it is hit by a bat so that it turns back and moves with a velocity of 20 metre per second find the impulse Impulse of the force the force acts for 0.01 second
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10 N/s
Explanation:
Actually impulse formula is (J=Ft)
F -force (ma)
t-time
here there are two conditions
1.at a=10 m/s
2.at a=20 m/s
when a=10
J=ft
=(100*10)*0.01
=10 N/s
when a=20
J=ft
= (100*20)*0.01
= 20 N/s
one is in forward direction and another is in backward direction so,
20-10 =10N/s
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