Question

A cricket ball of mass 100g moves with a velocity 20m/s. A batsman Stops the ball in 0.05
second. Find the force applied?
​

Answer 1

Answer:

Given mass of the ball as 100 g after converting to mks system it becomes 0.1 kg. As we know that acceleration is nothing but rate of change velocity and in this case we have initial velocity as 20m/s and final velocity as 0.

Step-by-step explanation:

a=(v−u)/t⇒

a=(0−20)/0.01=−2000m/s

f=m×a⇒

F=0.1×2000=200 N

The hand apply equal and opposite force of 200 N.

Answer 2

Given : A cricket ball of mass 100g moves with a velocity 20m/s & A batsman stops the ball in 0.05 second.

To Find : Find the force applied ?

________________________

$\underline{\frak{As~we~know~that~:}}$

• $\underset{\blue{\sf Acceleration\ Formula}}{\underbrace{\boxed{\frak{\pink{a~=~\dfrac{v~-~u}{t}}}}}}$

$~$

Where,

• a = Acceleration
• v = Final Velocity
• u = Initial Velocity

$~$

$:\implies\underset{\blue{\sf Force\ Formula}}{\underbrace{\boxed{\frak{\pink{F~=~ma}}}}}$

$~$

Where,

• F = Force
• m = Mass
• a = Acceleration

$~$

Solution : First, we have to convert g to kg :

• ${\sf{Mass~=~\dfrac{1}{1000}}}$

• $\pmb{\frak\green{Mass~=~0.1~kg}}$

$~$

Now, we have to find the acceleration :

Given :

• Final Velocity (v) = 0 m/s
• Initial Velocity (u) = 20 m/s
• Time (t) = 0.05 second

$~$

$\pmb{\sf{According~ to ~the~ Given ~Question~:}}$

$~$

• Using the formula we get,

$~$

$~~~~~~~~~~:\implies{\sf{a~=~\dfrac{0~-~20}{0.05}}}$

$~~~~~~~~~~:\implies{\sf{a~=~\dfrac{- 20~×~100}{5}}}$

$~~~~~~~~~~:\implies{\sf{a~=~\cancel\dfrac{- 2000}{5}}}$

$~~~~~~~~~~:\implies\pmb{\frak\purple{a~=~400~m/s^2}}$

$~$

Now, we have to find the force applied :

Given :

• Mass = 0.1 kg
• Acceleration = 400 m/s²

$~$

$\pmb{\sf{According~ to ~the~ Given ~Question~:}}$

$~$

• Using the formula we get

$~$

$~~~~~~~~~~:\implies{\sf{Force~applied~=~0.1~×~400}}$

$~~~~~~~~~~:\implies{\sf{Force~applied~=~\dfrac{1}{10}~×~400}}$

$~~~~~~~~~~:\implies \sf Force\: applied =\: \dfrac{ 40\cancel{0}}{1\cancel{0}}$

$~~~~~~~~~~:\implies\pmb{\frak\red{Force~applied~=~40~N}}$

Hence,

$\therefore\underline{\sf{The~force~applied~is~\bf{\underline{40~N}}}}$