Question

A cricket ball of mass 100g moving at a speed of 30 m/s is brought to rest by a player in 0.03s. Find the average force applied by the player. ans step by step

Answer 1

Answer:

We know , v-at 30=ax0.03

a=30/0.03=1000 m/s^2

So, F=ma=0.1x 1000100 N ans

Answer 2

➠ Questíon :-

➝ A cricket ball of mass 100g moving at a speed of 30 m/s is brought to rest by a player in 0.03s. Find the average force applied by the playrester.

➠ Gíven :-

➝ Mass, m = 100g

➝ object at rest, v = 30m/s

➝ time, t =0.03sec

➠ To fínd :-

➝ the average force applied by the player

➠ Solutíon :-

we know,

$\longrightarrow \tt v = at$

where,

• v = rest
• a = Acceleration
• t = time

$\longrightarrow \tt 30 = a \times 0.03$

$\longrightarrow \tt a = \frac{30 \times 100}{0.03 \times 100}$

$\longrightarrow \tt a = \cancel \frac{3000}{3}$

$\longrightarrow \tt a = 1000 {ms}^{ - 2}$

the average force applied by the player :-

$\longrightarrow \tt F = ma$

where,

• F = froce
• m = mass
• a = acceleration

$\longrightarrow \tt F =0.1 \times 1000$

$\longrightarrow \boxed {\tt F = 100N}$

Thus,the average force applied by the player is 100N.