a cricket ball of mass 100g moving at a speed of 30ms-1 is brought o rest by a player in 0.03s.find the average force applied by the player
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Answered by
30
Hi friend here is your answer.
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We know , v=at
30=a×0.03
a=30/0.03=1000 m/s^2
So, F=ma=0.1×1000=100N ans
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************************************
We know , v=at
30=a×0.03
a=30/0.03=1000 m/s^2
So, F=ma=0.1×1000=100N ans
*************************
nileshme:
thank you
Answered by
3
Explanation:
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