A cricket ball of mass 100g moving with a speed of 30m/s is brought to rest by a player in 0.03s. The average force applied by the player i
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Answer:
100000 N is the force applied by the man in the opposite direction of the motion of the ball
Explanation:
Mass of ball ia 100g
(U) =30ms-1
(V) = 0 ms-1
T =0.03
a=v-u/t=. 0-30/0.03
= - 30/0.03 = -3000/3 =-1000ms-2
= F= ma = 100 × - 1000= - 100000N
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